TS 10th Class Maths | Similar Triangles | Exercise 8.4 Q10 Proof | Kiran Sir Maths

Hey Students! Welcome back to KIRAN SIR MATHS 🎯 In this video, we solve and explain the highly important geometry proof involving an equilateral triangle where point D is on side BC such that BD = 1/3 BC, requiring us to prove that 9AD² = 7AB². Depending on your TS Syllabus / AP Class 10 Mathematics textbook edition, this is listed as Chapter 8 (Similar Triangles) Exercise 8.4 Question 9 or Question 10. Watch the full video to master the step-by-step logic and secure full marks! 📢 ONLINE & OFFLINE COACHING CLASSES AVAILABLE! If you are looking for dedicated coaching at Sri Manikanta Institute (Khammam) to score top marks in your board examinations, leave a comment below or contact us for batch details. 📋 Problem Statement Covered: "In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC. Prove that 9AD² = 7AB²." 💡 What You Will Learn in This Video: • Drawing a clean geometric diagram with altitudes for equilateral triangles. • Expressing segment lengths (BE, DE, BD) in terms of a single triangle side. • Applying the Pythagoras Theorem across internal right triangles (ΔAEC and ΔADE). • Easy algebraic simplification steps and LCM calculation to successfully arrive at the proof. If this video helped you clear your geometry doubts, please Like, Share, and Subscribe to Kiran Sir Maths for more TS Class 10 Maths solutions! #TS10thMaths #SimilarTriangles #Class10Maths #KiranSirMaths #SSCBoardExams #GeometryProofs #PythagorasTheorem #TelanganaMaths #AP10thMaths