McCabe Thiele with Material Balance | 100 kmol/h Feed | Distillate & Bottoms Calculation | Example 4
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McCabe Thiele with Material Balance | 100 kmol/h Feed | Distillate & Bottoms Calculation | Example 4
18 783 просмотра · 5 л. назад
Chemical adda
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18 783 просмотра · 5 л. назад
McCabe Thiele Example 4 - Complete solution with material balance.
Problem Statement: A rectification column is fed with 100 kmol/h of mixture containing 50 mol% hexane and 50 mol% octane at 101.325 kPa. Feed is at its boiling point. Distillate to contain 90 mol% hexane and bottoms 10 mol% hexane. Reflux ratio is 3.1. Calculate D and W (kmol/h) and number of theoretical trays.
In this video:
00:00 - Problem statement - Hexane Octane system
01:00 - Part 1: Material Balance to find Distillate (D) and Bottoms (W) flow rates
01:30 - Overall balance F = D + W, Component balance F*xF = D*xD + W*xW
03:10 - Calculation: D = 50 kmol/h, W = 50 kmol/h
04:00 - Part 2: McCabe Thiele method to find theoretical trays
04:30 - Plotting equilibrium data (given) and diagonal
05:45 - Drawing q-line for saturated liquid feed (q=1, vertical line)
06:30 - Drawing rectifying operating line with R=3.1
08:00 - Stepping off stages from (0.9, 0.9) to (0.1, 0.1)
This example is important because it has 2 parts - first find D & W, then find trays.
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