Class 8 Maths Ganita Prakash | Chapter 5 - Number Play | Figure it Out Page 122 & 123 Solutions

Class 8 Maths Ganita Prakash Solutions | Chapter 5 Number Play | Page 122 & 123 Figure It Out Solutions | New NCERT 2026-27 Welcome to Fun with Study! 📚✨ In this video, we cover Class 8 Maths Chapter 5: Number Play from the New NCERT Ganita Prakash Mathematics Book (2026-27). This video contains complete Figure It Out solutions for Page 122 & 123, Questions 1 to 8, explained step-by-step in an easy and simple way — useful for homework, revision, practice, and exam preparation. ✅ 📖 Page 122 – Figure It Out Solutions 00:00 Q1: The sum of four consecutive numbers is 34. What are these numbers? 04:01 Q2: Suppose p is the greatest of five consecutive numbers. Describe the other four numbers in the sequence in terms of p. 06:13 Q3: For each statement below, determine whether it is always true, sometimes true, or never true. Justify using algebra and examples: • (i) 06:41 The sum of two even numbers is a multiple of 3. • (ii) 08:34 If a number is not divisible by 18, then it is also not divisible by 9. • (iii) 10:03 If two numbers are not divisible by 6, their sum is also not divisible by 6. • (iv) 11:47 The sum of a multiple of 6 and a multiple of 9 is a multiple of 3. • (v) 14:31 The sum of a multiple of 6 and a multiple of 3 is a multiple of 9. 16:13 Q4: Find a few numbers that leave a remainder of 2 when divided by 3, and a remainder of 2 when divided by 4. Write an algebraic expression to describe all such numbers. 📖 Page 123 – Figure It Out Solutions 20:20 Q5: Pebble Riddle — When grouped in 3s, 2s, or 5s, 1 pebble remains; when grouped in 7s, no pebbles remain (Total under 100). Find the number of pebbles. 25:18 Q6: Tathagat writes several numbers that leave a remainder of 2 when divided by 6. He claims that the sum of any three such numbers will always be a multiple of 6. Is his claim true? 28:21 Q7: 661 leaves remainder 3 when divided by 7, and 4779 leaves remainder 5. Without calculating, find the remainders for: • (i) 29:00 (4779 + 661) ÷ 7 • (ii) 31:55 (4779 - 661) ÷ 7 33:16 Q8: Find the smallest number that leaves remainder 2 when divided by 3, remainder 3 when divided by 4, and remainder 4 when divided by 5. Give a simple explanation. 🎥 Watch the complete Class 8 Maths Chapter 5: Number Play playlist here:    • Number Play | Class 8 Maths | Chapter 5 | ...   Thank you for watching! ❤️ Keep Learning, Keep Growing with Fun with Study! 📚✨ #ganitaprakash8ch5figureitout #ganitaprakash8chapter5 #ganitaprakash8numberplay #ganitaprakash #class8maths #ncertclass8 #cbseclass8 #figureitout #class8mathssolutions #numberplay #class8mathsganitaprakash #funwithstudy #NCERTSolutions #NewNCERT2026_27 ganita prakash class 8 chapter 5 solutions, ganita prakash class 8 chapter 5 one shot, ganita prakash class 8 chapter 5 number play, ganita prakash class 8 chapter 5 number play explanation, ganita prakash class 8 chapter 5 number play figure it out, ganita prakash class 8 chapter 5 figure it out, ganita prakash class 8 chapter 5 question answer, ganita prakash class 8 chapter 5 page 122, ganita prakash class 8 chapter 5 page 123, ganita prakash 8 page 122 123, class 8 ganita prakash chapter 5 figure it out page 122, class 8 maths ganita prakash chapter 5 number play, class 8 maths ganita prakash chapter 5 explanation, class 8 maths ganita prakash chapter 5 exercise, class 8 maths book ganita prakash chapter 5, class 8 maths chapter 5 new book ganita prakash, class 8 maths chapter 5, class 8 maths number play, class 8 maths solutions, class 8 maths page 122, class 8 maths page 123, ncert class 8 maths, ncert class 8 maths solutions, cbse class 8 maths, new ncert 2026-27, ganita prakash mathematics, fun with study