Derivation 30/65 | Force Between Two Parallel Current Carrying Wires | Class 12 Physics

Derivation 30/65 – Force Between Two Parallel Current-Carrying Wires | Class 12 Physics Why do two parallel current-carrying wires attract or repel each other? In this video, we derive the force between two parallel current-carrying wires step by step, an important topic from the CBSE Class 12 Physics chapter Moving Charges and Magnetism. 📚 Topics Covered in This Video: Magnetic field due to a long straight current-carrying wire Force experienced by a current-carrying conductor in a magnetic field Derivation of the force between two parallel current-carrying wires Formula for force per unit length Attraction between wires carrying currents in the same direction Repulsion between wires carrying currents in opposite directions 📌 Important Formula: Force per unit length between two parallel current-carrying wires: F/L = μ₀I₁I₂/(2πd) Where: F = Magnetic force between the wires L = Length of the wires I₁ and I₂ = Currents in the two wires d = Distance between the wires μ₀ = Permeability of free space 🎯 Class 12 Physics Derivations Series – 30/65 This series covers important derivations for CBSE Class 12 Physics board examinations, helping students understand the concepts and prepare effectively. 📢 CBSE Test Series starts 14 November! Prepare for your CBSE Board Exams with Shree Ram Educators. 📍 Address: KB Plaza, Sector 2, Greater Noida West 🎓 Classes 9–12 | CBSE Board Preparation | JEE & NEET Foundation | PCM & PCB Physics by Vikas Sir | Shree Ram Educators Subscribe for more Class 12 Physics derivations, conceptual explanations, and board exam preparation videos. #Class12Physics #MovingChargesAndMagnetism #PhysicsDerivations #CBSEBoardPreparation #JEEPhysics #PhysicsByVikasSir #ShreeRamEducators