Isochoric and Isobaric Processes | JEE 2027 Chemistry (English)
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Isochoric and Isobaric Processes | JEE 2027 Chemistry (English)
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RankDeterminant
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This chapter: • Work in Ideal-Gas Processes | JEE Chemistr...
All lessons of this unit: • JEE 2027 Chemistry | Unit 4 Chemical Therm...
Isochoric and isobaric processes of an ideal gas: why w = 0 at constant volume so q = ΔU = nCvΔT while ΔH is still nCpΔT, why w = -nRΔT and q = ΔH at constant pressure, the topper's ratio q : ΔU : (-w) = Cp : Cv : R (7:5:2 diatomic, 5:3:2 monatomic), and two JEE-style solved problems on helium with the ΔH trap.
Chapters
0:00 Introduction
0:32 Two processes, two new words
1:29 Isochoric: no work at all
2:37 Isobaric: the gas pushes the piston
3:43 Topper's trick: where does the heat go?
4:46 Example 1: heating 2 mol helium at constant volume
6:06 Example 2: same heating at constant pressure, q, w, Delta U
7:56 Quick revision: isochoric vs isobaric, q : Delta U : -w
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Chemistry · Unit 4 · Chemical Thermodynamics · Chapter 2 · Work in Ideal-Gas Processes
#IsobaricProcess #JEEChemistry #JEE2027
Narrated with a computer voice.