MOI of a Thin Rod About CM | Why ML²/12? Easy Derivation | JEE & NEET

Understand the moment of inertia of a uniform thin rod about an axis passing through its centre of mass and perpendicular to its length. Learn the step-by-step derivation of I = ML²/12 using integration. ✅ Choose a small mass element: dm = (M/L) dx ✅ Apply dI = x² dm ✅ Integrate from −L/2 to +L/2 ✅ Understand the role of symmetry and the rotation axis Build your rotational motion concepts for Class 11 Physics, JEE, and NEET. Subscribe to Momentum Physics Academy for clear explanations and more physics problems! #MomentOfInertia #ThinRod #RotationalMotion #JEEPhysics #NEETPhysics