Count Partitions with Even Sum Difference | Leetcode 3432 | DSA | Hindi | Code With Deepak

In this video, we solve Leetcode 3432. Count Partitions with Even Sum Difference using Java. Question Link - https://leetcode.com/problems/count-p... Solution: https://github.com/deepak-sharma-iOS/... Summary: This solution first computes the total sum of the array, then iterates over all possible split points while maintaining the running left sum. At each split, it checks whether the difference between left and right partitions is even (i.e., (right - left) % 2 == 0), and if so, counts that partition as valid. The final count represents how many valid partitions satisfy the required parity condition. Subscribe -    / @debugwithdeepak   Github - https://github.com/deepak-sharma-iOS/... Linkedin -   / deepak-sharmaa-dev   #CodeWithDeepak #LeetCodeDailyChallenge #LeetCodeSolutions #DSAforInterviews #CodingWithExplanation #TechInterviewPrep #CrackTheCodingInterview #DailyCodingChallenge #JavaCoding #LearnToCode #CodingShorts #leetcodedailychallenge #euclidean