LeetCode 18: 4Sum | Sorting + Two Pointers | Java Solution

In this video, we solve LeetCode 18 – 4Sum using the Sorting + Two Pointers technique in Java. We’ll learn how to find all unique quadruplets whose sum equals the given target while efficiently handling duplicate values. 🔹 Problem: 4Sum 🔹 LeetCode: 18 🔹 Approach: Sorting + Two Pointers 🔹 Language: Java 🔹 Time Complexity: O(n³) 🔹 Space Complexity: O(1) excluding the output This problem is a great extension of 3Sum and helps strengthen your understanding of Arrays, Sorting, Two Pointers, and Duplicate Handling. #LeetCode #Java #DSA #4Sum #LeetCode18 #TwoPointers #Sorting #CodingInterview #Programming #DSAInJava