LeetCode 724 | Find Pivot Index | Sum based Approach

In this video, I solve the Pivot Index problem using an optimized approach. Idea: Instead of recalculating sums for every index, I first compute the total sum of the array. Then I traverse the array while maintaining a running left sum. At each index, I check if: left sum == total sum − left sum − current element If the condition is satisfied, that index is the pivot index. Complexity: Time Complexity: O(n) Space Complexity: O(1) This is a great example of using prefix sum concepts to reduce time complexity and write clean, efficient code. Code implemented in C++ #DSA #Coding #LeetCode #CPP #Algorithms #DataStructures #ProblemSolving