Remainder Using Binomial Theorem | JEE Main 2027 Maths (English)

Free notes + solved JEE problems for this lesson: https://rankdeterminant.com/go/yt-mat... All lessons of this unit:    • JEE 2027 Maths | Unit 5 Binomial Theorem   How to find the remainder of a huge power, like 7^100 divided by 8, with the binomial theorem: write the base or a small power as km ± 1, expand, fix a negative remainder, and prove divisibility results such as 3^(2n+2) - 8n - 9 divisible by 64. Two solved JEE problems from the course, with the classic traps. Chapters 0:00 Introduction 0:31 The idea: write 7 as 8-1 1:42 Tools for remainders 3:09 Divisibility: (1+x)ⁿ-nx-1 and x² 4:07 Example 1: remainder when 5^99 is divided by 13 5:48 Example 2: prove 3^(2n+2) - 8n - 9 is divisible by 64 7:43 Quick revision: km ± 1, negative remainders, divisibility A free JEE paper every day and a full JEE Main mock every Sunday: https://rankdeterminant.com/go/yt-dai... Mathematics · Unit 5 · Binomial Theorem · Chapter 5 · Greatest Term, Divisibility and Remainders #BinomialRemainder #JEEMaths #JEE2027 Narrated with a computer voice.