JEE Advanced Physics: Minimum Friction for a Leaning Body (Rotational Equilibrium)

Welcome back! In today's video, we are tackling a medium-difficulty JEE Advanced problem focusing on translational and rotational equilibrium. If you're studying for your exams, understanding how to balance forces and torques is critical. We'll walk through the entire free body diagram and derive the general formula before applying it to some common shapes. What You'll Learn in This Video: *The Setup:* Analyzing a symmetrical rigid body with a flat base of length L that rests on a rough horizontal floor and a smooth vertical wall. *Force & Torque Balance:* Step-by-step breakdown of vertical forces, horizontal forces, and calculating the net torque about the ground contact point to prevent rotational slipping. *The General Solution:* Deriving the minimum coefficient of static friction required to prevent the body from slipping, resulting in the formula: μ = (cot θ / 2) - (y_cm / L). *Special Cases & Applications:* We'll also apply this derived formula to standard shapes, including: Uniform Thin Rod Semicircular Wire/Ring Semicircular Disc/Plate Hollow & Solid Hemispheres Triangular Lamina --- *Practice Along With Me!* Try the problem yourself before watching the solution here: [https://physicsma.com/practice?proble...](https://physicsma.com/practice?proble...) Drop a comment below if you have any questions about finding the center of mass or balancing the torques! #RotationalMotion #TranslationalEquilibrium #RotationalEquilibrium #Torque #CenterOfMass #StaticFriction #RigidBodyDynamics #PhysicsConcepts #IITJEE #JEEAdvanced #JEEMain #NEET #APPhysics #IBPhysics #JEEPhysics #JEEPrep #EngineeringEntrance Channel & Brand Identity: #Physicsma #ManishArya #PhysicsProblems