Find the Limit of a Function using L'Hôpital's Rule

Find the limit of a function where the numerator f(x) = 3^x-3^-x and g(x) = 2^x=2^-x , The initial value at zero gives us a 0/0 situation which is undefined . This is one of the rules required for L'Hôpital's . The other is that the function f(x)/g(x) where f(x) and g(x) are both continuous and differentiable . Then we take the limit x approaches 0 of f'(x)/g'(x) and we do this 3 times as the first 2 give us a 0/0 situation . There is a graph at the end of the video showing the graph of the function (3^x-3^-x)/(2^x=2^-x) powered by https://www.transum.org/Maths/Activit...    • Use L'Hopitals Rule to find the limit of s...      • Use L'Hopitals Rule to find the limit of c...      • Using L'Hôpital's Rule to Find The Limit   #calculus #limits #algebratricks #limitsandderivatives #derivativeformulas #derivativeofcos #lhopital #realanalysis #calc3 #sumchief #somesums