LeetCode 2265 - Count Nodes Equal to Average of Subtree | C++ Solution in English | Code with Jillu

🔥 LeetCode 2265 - Count Nodes Equal to Average of Subtree In this video, we solve LeetCode 2265, Count Nodes Equal to Average of Subtree, using C++ and explain the complete approach in English. 🧠 Problem: Given the root of a binary tree, count the number of nodes where the value of the node is equal to the average of all values in its subtree. 💡 Approach: • Use Depth First Search (DFS) • For every node, calculate the sum of its subtree • Calculate the number of nodes in its subtree • Find the integer average • Check whether the current node value equals the subtree average • Return the total count 💻 Language: C++ 🧩 Topic: Binary Tree + DFS ⏱️ Time Complexity: O(n) 💾 Space Complexity: O(h), where h is the height of the tree 🎯 In this video: ✔️ Problem explanation ✔️ DFS intuition ✔️ Subtree sum and count ✔️ Step-by-step dry run ✔️ C++ solution ✔️ Time and space complexity If you found this video helpful, LIKE 👍, SHARE 📤 and SUBSCRIBE 🔔 to Code with Jillu. #LeetCode #LeetCode2265 #CountNodesEqualToAverageOfSubtree #Cpp #CPlusPlus #DSA #BinaryTree #DFS #Coding #CodeWithJillu #CompetitiveProgramming