Parallel Plates Electric Potential Difference using an Integral

For two large, oppositely charged parallel plates with a uniform electric field between them, this video derives the electric potential difference from plate A to plate B, ΔV = -Ed, as a special case of the general ΔV = -∫E·dr equation, using that the field is constant in magnitude and parallel to the displacement across the gap of distance d. It then explains what the negative sign means: the electric field points in the direction of decreasing potential, so a charge moving in the direction of the field experiences a negative potential difference, while a charge moving against the field experiences a positive one. Want Lecture Notes? http://www.flippingphysics.com/parall... Chapters: 0:00 Deriving Electric Potential Difference 1:30 What does the negative mean? Thank you to Beth Baran and the rest of my wonderful Patreon supporters. Please consider supporting me monthly at   / flippingphysics   Thank you to Carl Hansen, Julie Langenbruner, and John Paul Nichols for being my Quality Control Team for this video. http://flippingphysics.com/quality-co... Gracias a Llorenç Puig por editar las traducciones al español de este video. This video has been dubbed using an artificial voice via https://aloud.area120.google.com to increase accessibility. You can change the audio track language in the Settings menu. #ParallelPlates #ElectricField #Integral Curriculum Standards: AP Physics C: E&M, Unit 9 Electric Potential, Topic 9.2 Electric Potential 9.2.B.2: "The change in electric potential between two points can be determined by integrating the dot product of the electric field and the displacement along the path connecting the points." 9.2.B.3.iii: "An electric field vector points in the direction of decreasing potential." Cambridge International A Level Physics (9702), Topic 18.2 Uniform Electric Fields 18.2.1: "Recall and use E = ΔV/Δd to calculate the field strength of the uniform field between charged parallel plates."