LeetCode 1217 | Minimum Cost to Move Chips to The Same Position | Easy Problem | C++ Solution

In this video, I explain the problem step-by-step, discuss the optimal greedy approach, and implement the solution live while coding. 🚀 Problem: LeetCode 1217 – Minimum Cost to Move Chips to The Same Position 🧠 Approach: Observe the movement cost rules: Moving a chip by 2 positions costs 0 Moving a chip by 1 position costs 1 Count: Number of chips at even positions Number of chips at odd positions To make all chips meet at the same position: Move the smaller group to the larger group Return the minimum of: even count odd count ⏱ Time Complexity: O(n) 📦 Space Complexity: O(1) 🔗 GitHub Repository: https://github.com/VishwaPatel892/Lee... 👨‍💻 LeetCode Profile: https://leetcode.com/u/vishwa0102/ 💼 LinkedIn:   / vishwa-patel-9bab9639a   📝 Notes: Greedy observation-based problem Parity (odd/even) is the key concept Moving by 2 positions is free Simple and efficient one-pass solution #leetcode #leetcode1217 #dsa #algorithms #coding #programming #codinginterview #interviewprep #greedy #math #leetcodeeasy #problemSolving #learncoding #codewithme #developerlife #tech #placements #softwareengineer #codinglife #100daysofcode 👍 Like | Comment | Subscribe for more LeetCode solutions!