Class (12) Reaction Of LiAlH4 With Carboxylic Acid #Jee#Neet

LiAlH₄ Reaction with Carboxylic Acid | JEE & NEET PYQ | Organic Chemistry In this video, we discuss the important reduction reaction of carboxylic acids with Lithium Aluminium Hydride (LiAlH₄), a highly important reaction for JEE Main, JEE Advanced and NEET Organic Chemistry. Reaction: R–COOH —LiAlH₄ / dry ether→ R–CH₂OH followed by H₃O⁺ work-up LiAlH₄ is a strong reducing agent that converts a carboxylic acid into a primary alcohol. The video explains the reaction step-by-step, including the role of LiAlH₄, hydride transfer and the final acidic work-up. We also discuss important NCERT-based concepts, reaction mechanisms, product prediction and PYQ-type questions frequently asked in competitive examinations. This topic is useful for understanding the reduction of different carbonyl compounds and for comparing the reactions of carboxylic acids, esters, aldehydes and ketones with LiAlH₄. 📚 For: JEE Main • JEE Advanced • NEET • Class 12 NCERT 🧪 Topic: Reduction of Carboxylic Acid ⚡ Reagent: LiAlH₄ 🎯 Focus: Concept + Mechanism + PYQs + Product Prediction Subscribe for more JEE & NEET Organic Chemistry reactions and PYQs.