LeetCode 3886: Sum of Sortable Integers | Java Solution & Visual Dry Run | DrawToCode
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LeetCode 3886: Sum of Sortable Integers | Java Solution & Visual Dry Run | DrawToCode
457 просмотров · 9 дней назад
LivingCode
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457 просмотров · 9 дней назад
*LeetCode 3886: Sum of Sortable Integers*
In this video, we solve the *Hard LeetCode problem Sum of Sortable Integers* using a step-by-step visual explanation with **DrawToCode**.
🖊 *Create your own DSA visualizations:*
https://drawtocode.org/drawtocode?vis...
📌 *Problem Link:*
https://leetcode.com/problems/sum-of-...
💡 What You'll Learn
Understand what makes an integer `k` sortable.
Learn why `k` must be a divisor of the array length.
Understand how cyclic rotations can transform array blocks.
Learn how to compare individual blocks with the corresponding segments of the sorted array.
Explore efficient divisor enumeration and the Java implementation.
Perform a step-by-step visual dry run with examples.
Handle edge cases and analyze time and space complexity.
🧠 *Approach:* Divisor Enumeration + Cyclic Rotation Checks
💻 *Language:* Java
⏱ *Time Complexity:* O(n√n) for the straightforward divisor-checking approach
💾 *Space Complexity:* O(n)
⏱️ Video Chapters
00:00 Introduction
00:25 Problem Statement and Requirements
03:17 Understanding Cyclic Rotations
05:39 What Makes an Integer Sortable?
07:07 Example 1: `nums = [3, 1, 2]`
09:55 Two Important observations
11:00 Observation 1 : Can a Subarray be Sorted by Rotation ?
13:00 Observation 2 : Subarray must be in the correct order
16:50 Step-by-Step Algorithm
19:10 Step-by-Step Java Code Explanation
🚀 *Explore more interactive DSA visualizations:*
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Practice algorithms visually, understand complex logic step by step, and improve your problem-solving skills with DrawToCode.
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