GFG POTD | Max Adjacent Diffs Sum with 1 Replacements | Recursion + DP | C++

GFG POTD – Max Adjacent Diffs Sum with 1 Replacements In this video, we solve *Max Adjacent Diffs Sum with 1 Replacements* using two approaches. First, we understand the *brute force recursion* approach to explore the possible replacements. Then, we optimize the solution using *Iterative DP* to efficiently calculate the maximum sum of adjacent differences. *Approaches Covered:* Brute Force Recursion Iterative DP *Time Complexity:* O(n) *Space Complexity:* O(1) for optimized DP *Language:* C++ Problem Link : https://www.geeksforgeeks.org/problem... Source Link : https://github.com/Krishnkantm/DSA-Co... This problem is a good example of how a recursive solution can be converted into an efficient DP solution. If you found the video helpful, like the video and subscribe to *Logic Mode* for more GFG POTD and DSA solutions. #GFG #GFGPOTD #DP #DynamicProgramming #Recursion #Cplusplus #DSA #LogicMode