Motion in straight line Class 11 PHYSICS | NEET JEE EAPCET | Concepts + Easy to Advanced Problems
Physics Class KRD Mam By Vedantu
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Motion in straight line Class 11 PHYSICS | NEET JEE EAPCET | Concepts + Easy to Advanced Problems
21 582 просмотра · Трансляция закончилась 1 месяц назад
Physics Class KRD Mam By Vedantu
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21 582 просмотра · Трансляция закончилась 1 месяц назад
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⚡ Master Motion in a Straight Line – Class 11 Physics with a clear explanation of every important concept and carefully selected problems. This complete lesson is useful for students preparing for JEE Main, JEE Advanced, NEET, AP EAPCET and TG EAPCET.
In this video, Rama Mam explains the chapter from basic to advanced level, helping you understand concepts, formulas and problem-solving methods. Practice important questions and previous-year questions to improve your speed, accuracy and confidence.
📚 TOPICS COVERED:
0:00 – Intro
1:43 – Weightage & why this chapter can't be skipped
4:58 – Topics covered in this class
6:52 – Distance vs Displacement: definitions, scalar/vector
10:03 – Example: man walking on a number line
13:11 – Circle-based problems (quarter, half, 3/4 circle)
16:52 – Arc/sector: distance = rθ, displacement = 2r sin(θ/2)
22:37 – Displacement with directions (i, j, k)
24:22 – JEE PYQ: sportsman on circular track (ABAB)
25:54 – PYQ: cyclist P to S displacement
27:07 – Problem: body completing revolution in 4 s
29:33 – Problem: displacement using cos 135° (triangle law)
34:55 – Problem: t = √x + 3 → distance & displacement (table method)
38:58 – Problem: athlete 140 s on circular track
40:21 – Problem: rolling wheel point P displacement
42:53 – Drunkard problem
45:48 – Speed & Velocity: average speed/velocity formulas
50:56 – Instantaneous speed/velocity, calculus formulas
55:09 – Problem: x = 6t² − 12t + 10 (U-turn logic, velocity = 0)
1:03:09 – Average speed & velocity in 2 s and 3 s
1:07:00 – Problem: x = 2t² − 20t + 10, avg speed in 10 s
1:11:56 – Acceleration: constant vs variable, equations of motion
1:16:41 – Trick: same vehicle in two cases = constant acceleration
1:17:56 – Problem: acceleration opposite to velocity (body stops)
1:25:42 – Applications of average speed: Case 1 (half distance)
1:29:59 – Case 2 (three equal parts), Case 3 (to and fro)
1:33:43 – Case 4 (half time), general formula
1:35:07 – Problem: 1/3 distance + half-time (trick: start with case 2)
1:40:04 – Problems: three equal parts, v₀ + half times
1:46:04 – Problem: 40 m in 5 s, 70 m in next 5 s (trick: combine cases)
1:52:07 – Reaction time concept + problem
2:00:41 – Calculus problems: x = 2t + 3t², s = t³ − 6t² + 3t + 7
2:03:10 – Problems: body at rest, t = √x + 3, xy-plane
2:09:02 – v = √(3x + 16): comparison method
2:13:24 – Problem: x₁ and x₂ in half times (x₂ = 3x₁)
2:18:33 – Homework: automobile braking (50 → 90 km/h)
2:22:00 – Problem: distances a and b in successive equal times
2:24:42 – JEE/NEET PYQ: t = ax² + bx, find acceleration
2:30:47 – Graphs: x-t, v-t, a-t; slope & area meaning
2:35:22 – Slope analysis (positive, negative, constant, curved)
2:41:35 – Problem: where is instantaneous velocity negative
2:42:46 – Problem: a-t graph → max speed (area)
2:44:36 – NCERT: v_A/v_B from angles
2:45:24 – v-t graph: displacement vs distance (signed area)
2:49:14 – Converting v-t graph to a-t graph
2:51:50 – v-s graph → a-v graph; v²-s graph → acceleration
2:55:17 – Accelerate-then-retard model: v_max, total time, distance
3:01:20 – Motion under gravity: freely falling body formulas
3:05:40 – Body thrown upwards: from ground & from tower
3:11:13 – Problem: two bodies dropped 2 s apart (40 m separation)
3:14:15 – Problem: stone from tower, reaches ground with 3u
3:16:25 – Water drops problem (4th drop height)
3:21:15 – Problem: last second covers half distance (quadratic)
Watch the complete video, make notes and solve every problem along with the explanation. This session will help you build a strong foundation in kinematics and prepare confidently for entrance examinations.
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Best wishes for your JEE, NEET & EAPCET preparation!