Gas Station ⛽ | Greedy Algorithm Explained in C++ | LeetCode 134 | DSA Series #74

Welcome to Day 74 of my DSA Journey! Today, I solved Gas Station (LeetCode 134) — a classic Greedy Algorithm problem that teaches us how to find the correct starting point in a circular route efficiently. 💡 Problem Overview You are given two arrays: gas[i] — the amount of gas available at station i cost[i] — the gas required to travel from station i to the next station You need to find the starting gas station index from which you can travel around the entire circuit exactly once. If completing the circuit is impossible, return -1. 🧠 Key Idea The greedy approach is based on two important observations: If the total gas is less than the total cost, completing the circuit is impossible. While traversing the stations, if our current tank becomes negative, the current starting point cannot be the answer. We reset the starting point to the next station and continue. If the total gas is sufficient, the final valid starting point gives us the answer. This turns a potentially complex circular problem into a simple one-pass greedy solution. 🚀 ⏱️ Complexity Time Complexity: O(n) Space Complexity: O(1) 📚 Resources 🎓 DSA Learning: ChaiCode: https://dsa.chaicode.com/signup?ref=N... Day 74 ✅ — DSA Journey Continues! #DSA #LeetCode #LeetCode134 #GasStation #GreedyAlgorithm #CPlusPlus #CPP #Coding #Programming #DSAJourney #100DaysOfCode #LearningInPublic #ChaiCode #ProblemSolving