🔥 LeetCode 678 – Valid Parenthesis String | Java | Greedy Approach

🔥 LeetCode 678 – Valid Parenthesis String | Java | Greedy Approach In this video, we solve LeetCode 678: Valid Parenthesis String using an efficient Greedy approach in Java. The string contains (, ) and *, where * can be treated as: ( ) Empty string "" 💡 What You'll Learn ✅ Greedy Range Technique ✅ minOpen & maxOpen concept ✅ How to handle * efficiently ✅ Step-by-step dry run ✅ Java implementation ✅ Time & Space Complexity ✅ Interview-focused explanation 🚀 Complexity Time: O(n) Space: O(1) 📌 LeetCode: 678 📌 Topic: Greedy / Strings / Stack Concepts 📌 Language: Java If you're preparing for DSA, LeetCode, coding interviews, placements, TCS, Infosys, Accenture, Amazon, Microsoft, this is an important problem to practice. 👍 Like the video if it helped! 💬 Comment your approach below. 🔔 Subscribe for more Java DSA & LeetCode solutions. #LeetCode #LeetCode678 #ValidParenthesisString #DSA #Java #Greedy #CodingInterview #JavaDSA #LeetCodeSolutions #Programming #PlacementPreparation #Coding #InterviewPreparation