Maximum Frequency with K Increments | Sliding Window | GFG POTD | C++

🔥 GFG POTD — Maximum Frequency with K Increments In this video, we solve Maximum Frequency with K Increments using Sorting + Sliding Window. We can increment any element by 1 in one operation, and the goal is to make as many elements as possible equal using at most k operations. 🧠 Key Observation After sorting the array, consider a window [l...r]. We try to make every element in the window equal to arr[r]. The number of operations required is: arr[r] × window_size − window_sum If this cost becomes greater than k, we shrink the window from the left. This lets us find the maximum valid window efficiently. 💡 Why Sorting Helps? Because the array is sorted, arr[r] is the largest element in the current window. So every other element can be increased toward arr[r] without needing to decrease anything. ⏱️ Complexity Sorting: O(N log N) Sliding Window: O(N) Total: O(N log N) Space: O(1) apart from sorting 💻 C++ Code: https://github.com/PiyushKumar23-12/A... Code se zyada, Soch Samjho. ❤️ #GFGPOTD #DSA #SlidingWindow #Cpp #GeeksforGeeks #CompetitiveProgramming