Ratio of Consecutive Binomial Coefficients | JEE 2027 Maths (English)
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Ratio of Consecutive Binomial Coefficients | JEE 2027 Maths (English)
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RankDeterminant
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All lessons of this unit: • JEE 2027 Maths | Unit 5 Binomial Theorem
How to find n and r when three consecutive binomial coefficients are in a given ratio: decide which coefficients the question means, use the ratio of neighbours to get two equations, multiply by k for (1 + kx)^n, the A.P. condition (n - 2r)^2 = n + 2, why they are never in G.P. or H.P., and two solved JEE-style problems.
Chapters
0:00 Introduction
0:32 First decide: which three coefficients?
1:50 Ratio of neighbours: two equations
3:06 Progressions: A.P. possible, G.P. and H.P. never
4:36 Example 1: coefficients in ratio 1:2:3, find n and r
6:13 Example 2: (1 + 3x)^n coefficients in ratio 1:8:42
7:51 Quick revision: ratio equations, A.P. test, never G.P.
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Mathematics · Unit 5 · Binomial Theorem · Chapter 3 · Coefficients: Conditions and Products
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Narrated with a computer voice.