9th Class Physics numerical 6.11 | Class 9 Physics Numerical 6.11 | 9th Physics Numerical 6.11
Sir Bilal Saleem
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9th Class Physics numerical 6.11 | Class 9 Physics Numerical 6.11 | 9th Physics Numerical 6.11
49 просмотров · 1 мес. назад
Sir Bilal Saleem
886 подписчиков
49 просмотров · 1 мес. назад
Class 9 Physics | Chapter 6 Mechanical Properties of Matter | Numerical 6.11 | Hydraulic Press | New Book 2025
In this lecture, we solve Numerical 6.11 from Chapter 6 Mechanical Properties of Matter of Class 9 Physics (Punjab Textbook Board – New Syllabus 2025).
This numerical is based on pressure in a hydraulic press and the relationship between pressure, force, and cross-sectional area.
The question states that the pressure in a hydraulic press is increased by an additional 10 N cm⁻². We are asked to calculate how much extra load can be supported by the output platform when its cross-sectional area is 50 cm².
📘 Given Data:
Additional pressure = 10 N cm⁻²
Area of output platform = 50 cm²
We use the formula:
👉 Pressure = Force ÷ Area
Rearranging:
👉 Force = Pressure × Area
Substituting the given values:
👉 F = 10 × 50
👉 F = 500 N
✅ Final Answer: 500 N
🔎 What You Will Learn in This Video
✅ Relationship between pressure, force and area
✅ Application of Pascal’s Law
✅ Working principle of a hydraulic press
✅ How to calculate force from pressure
✅ Step-by-step numerical solving method
✅ Correct use of SI and practical units
✅ Board exam solving technique
📚 Concepts Covered
✔ Pressure
✔ Force
✔ Cross-sectional Area
✔ Hydraulic Press
✔ Pascal’s Law
✔ Mechanical Properties of Matter
✔ Hydraulic Machines
✔ Physics Numericals
✔ Board Exam Preparation
🎯 Why Numerical 6.11 Is Important
⭐ Important numerical from Chapter 6
⭐ Strengthens the concept of pressure
⭐ Helps understand hydraulic machines
⭐ Useful for board examinations
⭐ Improves numerical-solving skills
⭐ Helpful for MCQs and short questions
👉 Watch the complete Chapter 6 Mechanical Properties of Matter Playlist for complete preparation.
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