The 10-Second Shortcut for This Tricky Algebra Problem

In this video, we solve the algebraic equation: x^(1/10) + x^(1/15) + x^(1/30) = 84 Instead of taking the lengthy cubic substitution route, we look at a clean, smart observation trick: 1. Make denominators uniform: x^(3/30) + x^(2/30) + x^(1/30) = 84 2. Express 84 as powers of 4: 64 + 16 + 4 = 4³ + 4² + 4¹ 3. Directly compare terms to get x^(1/30) = 4, giving x = 4³⁰. This approach saves crucial time in JEE Main, JEE Advanced, and other competitive mathematics exams. 📌 Timestamps: 00:00 - Problem introduction: x^(1/10) + x^(1/15) + x^(1/30) = 84 00:30 - Standardizing the fractional exponents (LCM of denominators) 01:45 - Key insight: Decomposing 84 into powers 02:45 - Comparing terms and finding x 03:20 - Why avoiding lengthy substitution saves time Subscribe to @Siyesh_IIT-JEE for daily JEE problem-solving tricks and calculus/algebra deep-dives! jee advanced, jee main, jee maths, algebra tricks, algebra equation, exponential equation, math olympiad, how to solve exponential equations, basic mathematics jee, siyesh iit jee, jee 2025, jee 2026, iit jee preparation, calculation tricks for jee, algebraic manipulation #jee #jeeadvanced #jeemains #maths #algebra #jee #jeeadvanced #jeemain #maths #algebra #iitjee