📐 Lagrange Multiplier Method | Max & Min of 3x+4y on Circle x²+y²=1 ✅ | Calculus | Example 1 |

In this video, we solve a Lagrange multiplier problem step by step: Find the maximum and minimum values of f(x,y) = 3x + 4y on the circle x² + y² = 1. You will learn: ✔ How to form the auxiliary function F(x,y,λ) ✔ How to find the partial derivatives Fx and Fy ✔ How to solve for the stationary points ✔ How to find the maximum and minimum values Final answer: Maximum value = 5 at (3/5, 4/5) Minimum value = -5 at (-3/5, -4/5) ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━ 📚 RESOURCES & LINKS ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━ 📥 Download PDF Notes : https://engineeringmathematica.blogsp... 📲 WhatsApp Channel — Latest Updates & Tips: https://whatsapp.com/channel/0029VaAU... 💬 WhatsApp Direct — Got Questions? Message Me: https://wa.me/message/HM5KUVTAFENSA1 📢 Telegram — Download Study Materials: https://t.me/engineerinmathematica 🧠 Full Course Playlist — MA25C01-UNIT II:    • MA25C01-UNIT II - FUNCTION OF SEVERAL VARI...   📖 Read the full written solution with graph: (paste your blog link here) 👍 Like, share and subscribe for more engineering maths solved problems. #LagrangeMultiplier #Calculus #EngineeringMaths #MaximaMinima #Optimization