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Q23. This Infinite Series Looks Scary! | Narayana Mock Test| JEE Advanced 2027 | Om Sharma

Uplift Maths : OM Sharma Sir

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Q23. This Infinite Series Looks Scary! | Narayana Mock Test| JEE Advanced 2027 | Om Sharma

20 983 просмотра · 2 недели назад
Uplift Maths : OM Sharma Sir
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20 983 просмотра · 2 недели назад
✅Apply for OM Sir Mentorship https://docs.google.com/forms/d/e/1FA... 🚀 JEE ADVANCED EXPRESS Complete playlist:    • JEE ADVANCED EXPRESS: (Exceptional Brillia...   ✅ UPLIFT JEE Android App https://play.google.com/store/apps/de... website https://www.upliftjee.com https://www.upliftmaths.com ✅Msg on WhatsApp https://wa.me/917240569576 Three infinite series, factorials everywhere—and one expression to evaluate. Where should you begin? In this video, Om Sharma Sir explains the mathematical thinking behind this Narayana question and how to approach a complicated-looking expression systematically. Given: a = Σ x^(3n)/(3n)! b = Σ x^(3n+1)/(3n+1)! c = Σ x^(3n+2)/(3n+2)! (All sums run from n = 0 to ∞.) Find: a³ + b³ + c³ − 3abc Pause the video and attempt the question before watching the solution. Comment with your answer and the first idea you tried! Useful practice for JEE Advanced aspirants working on infinite series, exponential expansions and algebraic identities. Om Sharma | IIT Bombay Graduate | Pearson Author Explore more JEE Mathematics lessons:    / @omsharmasir   Question source: Narayana, as shown in the supplied question image. Solution and explanation by Om Sharma. Understand the Concepts. Develop the Thinking. UPLIFT your Maths. ✅FILL Google Form FOR Mentorship & Mastering MATHEMATICS https://docs.google.com/forms/d/e/1FA... #JEEAdvanced #JEEMaths #OmSharma