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Operons and Prokaryotic Control and Eukaryotic Gene Control and Cancer | Six Minutes: MCAT, Part 9

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Operons and Prokaryotic Control and Eukaryotic Gene Control and Cancer | Six Minutes: MCAT, Part 9

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Six Minutes
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0 просмотров · 4 ч назад
Six Minutes: MCAT, Part 9: Operons and Prokaryotic Control and Eukaryotic Gene Control and Cancer: B/B 1B: the Jacob-Monod model, repression, and positive control; then Eukaryotic Gene Control and Cancer Bacteria group related genes into operons controlled by a promoter and an operator. This episode explains the Jacob-Monod model, gene repression, and positive control, then works through a two-signal regulation problem. Then: Eukaryotic genes are controlled in layers: chromatin packing, DNA methylation, transcription factors, alternative splicing, amplification, and noncoding RNAs. Cancer arises when control breaks, through overactive oncogenes, lost tumor suppressors, and telomerase that keeps telomeres long. Chapters 0:00 Introduction 0:23 The operon idea 0:45 Negative control: repression 1:24 Positive control 1:41 Worked example 2:41 The trap 3:02 Recap 3:20 Eukaryotic Gene Control and Cancer 3:33 Layers of control 4:37 Splicing and amplification 5:10 When control breaks 5:50 Worked example 6:41 The trap 6:57 Recap 7:19 Thanks for watching Practice problems 1. In a made-up operon, a repressor binds the operator unless sugar X is present. If sugar X is added to cells, what happens to transcription, and why? Answer: Transcription turns on; sugar X acts as an inducer, binding the repressor so it releases the operator and RNA polymerase can transcribe the genes. 2. In a made-up operon, transcription is high only when an activator protein is bound; there is no repressor. If the activator cannot bind DNA, is this loss of positive or negative control, and what is the transcription level? Answer: Loss of positive control; transcription is low or absent because RNA polymerase rarely initiates without the activator. 3. A gene is amplified from 2 copies to 12 copies, and each copy makes 20 mRNAs per hour. If methylation silences 4 of the copies, how many mRNAs per hour does the cell make, and what is the fold change over the normal 40 mRNAs per hour? Answer: 8 active copies × 20 = 160 mRNAs per hour; 160 / 40 = 4×. 4. A cell loses one copy of a tumor suppressor gene and the remaining copy is overexpressed threefold. Is the brake likely lost? Answer: No. Tumor suppressors need loss of both copies; one remaining functional copy still provides the brake, and overexpression of it does not cause gain of function. Six Minutes @SixMinuteClass: One technique, about six minutes. The narrator's voice is synthetic (computer-generated). Independent educational video for exam study, not medical advice. Not affiliated with or endorsed by the AAMC (Association of American Medical Colleges). MCAT is a registered trademark of the AAMC. © 2026 Six Minutes · @SixMinuteClass