JEE Main Physics Thermodynamics #6 Thermodynamic Cyclic Process

Visit http://ilectureonline.com for more math and science lectures! To donate: http://www.ilectureonline.com/donate https://www.patreon.com/user?u=3236071 If one mol of an ideal gas at (P1,V1) is allowed to expand reversibly and isothermally (from A to B) its pressure is reduced to one-half of the original pressure (see figure). This is followed by a constant volume cooling till its pressure reduced to one-fourth of the initial value (B to C). Then it is restored to its initial state by a reversible adiabatic compression (C to A). The net work done by the gas is equal to: A) 0 B) (-RT)/[2(gamma-1)] C) RT{ln(2)-1/[2(gamma-1)]} D) RTln(2) Previous video in this series can be seen at:    • JEE Main Physics Thermodynamics #5 Kinetic...   Next video in this series can be seen at:    • JEE Main Physics Thermodynamics #7 Root Me...