Prove Tangents Drawn from External Point are Equal 🎯 | Theorem 10.2 Circles Class 10

Master Theorem 10.2 from Class 10 Maths Chapter 10 (Circles)! In this video, we prove step-by-step that "The lengths of tangents drawn from an external point to a circle are equal (PA = PB)." 📌 What You Will Learn in This Video: Theorem Statement & Concept: Understanding why tangents PA and PB drawn from an external point P are equal. Construction Steps: Joining center O to external point P and points of contact A & B. Congruence Proof (RHS Rule): \angle OAP = \angle OBP = 90^\circ (Radius \perp Tangent) OP = OP (Common hypotenuse) OA = OB (Radii of the same circle) \Delta OAP \cong \Delta OBP \implies PA = PB by CPCT. Additional Results: Proving tangents subtend equal angles at the center and are equally inclined to the line joining the center. ⏰ Timestamps: 00:00 - Introduction & Theorem Statement 01:20 - Diagram, Given, To Prove & Construction Setup 03:40 - RHS Congruence Step-by-Step Proof (PA = PB) 08:15 - Additional Results (\angle APO = \angle BPO and \angle AOP = \angle BOP) 11:30 - Important Board Exam Practice Questions & Recap 🔔 Subscribe for complete Class 10 Board Exam preparation, NCERT theorem proofs, and important questions! Hashtags #Class10Maths #CirclesClass10 #Theorem10_2 #Class10BoardExam #CBSEClass10 #MathsTheoremProof #NCERTMaths