Consider a PDA that accepts by empty stack, Now construct an equivalent CFG | 2080 Questions |
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Consider a PDA that accepts by empty stack, Now construct an equivalent CFG | 2080 Questions |
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GUPTA TUTORIAL
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In this video, we solve an important Theory of Computation (TOC) problem: Given a PDA that accepts by empty stack, construct an equivalent Context-Free Grammar (CFG).
Consider a PDA that accepts by empty stack, P=({p,q},{0,1},{Z},δ,p,z); with δ defined as
δ(p,0,z)=(p,0z), δ(p,0,0)=(p,00), δ(p,1,0)=(p,ε), δ(p,ε,z)=(q,ε),
Now construct an equivalent CFG.
In this video, we explain the step-by-step conversion of PDA into an equivalent CFG, including how to understand the PDA transitions and derive the corresponding grammar.
📌 Topics Covered:
✅ PDA accepting by Empty Stack
✅ Conversion of PDA to CFG
✅ PDA to CFG construction
✅ Understanding PDA transitions
✅ Context-Free Grammar (CFG)
✅ Derivation of CFG from PDA
✅ Language accepted by the PDA
✅ Exam-oriented solution
✅ Important Theory of Computation question
This video is especially useful for B.Sc.CSIT 4th Semester Theory of Computation (TOC) students preparing for TU Board Exams, previous-year questions, and internal examinations.
📚 Subject: Theory of Computation
🎓 Program: B.Sc.CSIT
📖 Topic: PDA to CFG Conversion
📝 Question Type: Construct an Equivalent CFG from PDA
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