An ideal gas (0.5 mol), initially at 2 bar pressure, is compressed | JEE Advanced Thermodynamics

jee advanced chemistry jee advanced chemistry pyq jee advanced chemistry thermodynamics jee advanced thermodynamics jee advanced pyq thermodynamics jee advanced questions thermodynamics jee advanced problems jee advanced 2026 jee advanced 2026 paper-1 solution jee advanced 2026 chemistry solutions In this video, Thermodynamics question that came in JEE Advanced 2026 paper-1 in explained. The question statement is An ideal gas 0.5 mol, initially at 2 bar pressure, is compressed at a constant temperature of 600 K in two steps: first, against a constant external pressure of P bar, and then against constant external pressure of 8 bar. At each step, the compression is stopped only when the pressure of the gas becomes equal to the external pressure. The total work done on the gas in these steps is W. Considering all possible values of P, and taking the gas constant as R, the minimum value of W in J is [a] 207R [b] 600R [c] 630R [d] 900R If you like the video, do subscribe the channel for more such solutions. Links of Playlists Electrochemistry JEE Advanced 2020-2026 PYQs :    • Electrochemistry JEE advanced PYQs (2020-2...   Chemical Kinetics JEE Advanced 2020-2026 PYQs:    • Chemical Kinetics JEE Advanced PYQs (2020-...   Chemical Thermodynamics JEE Advanced 2020-2026 PYQs:    • Chemical Thermodynamics JEE Advanced PYQs ...   Solutions JEE Advanced 2020-2026 PYQs:    • Solutions JEE Advanced PYQs (2020-2026)