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w=sin(z) as a Conformal Mapping

Mike, the Mathematician

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w=sin(z) as a Conformal Mapping

485 просмотров · 1 год назад
Mike, the Mathematician
26,5 тыс. подписчиков
485 просмотров · 1 год назад
We now consider the complex mapping w= sin(z). We know that this mapping is conformal away from the zeroes of cos(z), but we now examine the structure of the mapping. We show that this mapping takes a half strip, to the upper half plane. The images of the level sets in the xy plane are mapped to confocal ellipses and hyperbolae! #mikethemathematician, #mikedabkowski, #profdabkowski, #complexanalysis, #conformalmapping