Binomial Theorem with Conjugate Surds | JEE 2027 Maths (English)
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Binomial Theorem with Conjugate Surds | JEE 2027 Maths (English)
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RankDeterminant
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This chapter: • The Binomial Theorem | JEE Maths Unit 5, C...
All lessons of this unit: • JEE 2027 Maths | Unit 5 Binomial Theorem
How the binomial expansion turns surds into whole numbers: why the odd powers of root b cancel in (a+√b)^n + (a−√b)^n, why the difference is a multiple of root b, quick estimates with (1+x)^n 1+nx, and two solved JEE-style problems, including (√3+√2)^6 + (√3−√2)^6 = 970 by a faster squaring trick.
Chapters
0:00 Introduction
0:36 Conjugates: half the terms cancel
2:36 Estimates: the first few terms are enough
3:58 Example 1: find (root 2 + 1)^6 + (root 2 - 1)^6
5:20 Example 2: find (root 3 + root 2)^6 + (root 3 - root 2)^6
7:45 Quick revision: conjugate sums, differences and estimates
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Mathematics · Unit 5 · Binomial Theorem · Chapter 1 · The Binomial Theorem
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Narrated with a computer voice.