Oblique Impact with Ground Made Easy | Find \(e\) and V

A ball of mass \(m\), moving with velocity \(u\), strikes a smooth horizontal ground at an angle \(\theta\) with the vertical. It rebounds with velocity \(V\), making an angle \(\phi\) with the vertical. In this lesson, learn how to apply: Conservation of horizontal momentum Coefficient of restitution along the vertical normal Resolution of incident and rebound velocities Oblique-impact concepts For a smooth ground: $$ u\sin\theta=V\sin\phi $$ Therefore, the velocity after impact is: $$ \boxed{V=\frac{u\sin\theta}{\sin\phi}} $$ The coefficient of restitution is: $$ \boxed{e=\frac{V\cos\phi}{u\cos\theta} =\frac{\tan\theta}{\tan\phi}} $$ Perfect for JEE Main, JEE Advanced, NEET and Class 11 Physics. Tags ball rebound from ground, oblique impact, oblique collision with ground, coefficient of restitution, find rebound velocity, velocity after impact, ball ground collision, smooth ground collision, angle of incidence and rebound, collision problems JEE, coefficient of restitution problems, conservation of momentum, impact mechanics, JEE Advanced physics, NEET physics, class 11 physics, mechanics numericals, B V Reddy physics, Momentum Physics Academy Hashtags #ObliqueCollision #CoefficientOfRestitution #BallRebound #JEEPhysics #NEETPhysics #MomentumPhysicsAcademy A ball of mass m is moving with a velocity u , strikes the ground at an angle θ to the vertical and then rebounds with a velocity V, making an angel φ with the vertical. Find the coefficient of restitution and also the velocity after the impact.